{2 \times 1} = \frac{-2\pm \sqrt{-16}}{2 \times 1}\) It is not possible to find the square root of a negative number, so the equation has no solutions. The graph of \(y = x^2 + 2x + 5\) does not ...

So the equation \(x^2 + bx + c = 0 \) becomes ... right)^2 - c\) which can then be solved by taking the square root of both sides. Start by following the formula: \(x^2 + bx + c = \left(x ...